Please see attachment. (Answer is included.) This problem deals…

Please see attachment. (Answer is included.) This problem deals…

Please see attachment. (Answer is included.) This problem deals with

pipes in parallel. The head loss across each pipe will be the same and also the total flow rate into and out of this network must be equal to the sum of the flow rate through the individual pipes. Use the Resistance Coefficient (R) approach to quantify the head loss (hL = RQ2). Convert minor losses into equivalent lengths of pipe and just add them to the pipe lengths to calculate the R-values for each pipe to have far fewer terms.

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